net.sf.saxon.om

Class NodeArrayIterator

public class NodeArrayIterator extends ArrayIterator implements AxisIterator

An iterator over an array of nodes. This is the same as ArrayIterator, except that the iterator is an AxisIterator
Constructor Summary
NodeArrayIterator(NodeInfo[] nodes)
NodeArrayIterator(NodeInfo[] nodes, int start, int end)
Method Summary
Valueatomize()
Return the atomized value of the current node.
SequenceIteratorgetAnother()
Get another iterator over the same items
SequenceIteratorgetReverseIterator()
Get an iterator that processes the same items in reverse order
CharSequencegetStringValue()
Return the string value of the current node.
AxisIteratoriterateAxis(byte axis, NodeTest test)
Return an iterator over an axis, starting at the current node.
booleanmoveNext()
Move to the next node, without returning it.

Constructor Detail

NodeArrayIterator

public NodeArrayIterator(NodeInfo[] nodes)

NodeArrayIterator

public NodeArrayIterator(NodeInfo[] nodes, int start, int end)

Method Detail

atomize

public Value atomize()
Return the atomized value of the current node.

Returns: the atomized value.

Throws: NullPointerException if there is no current node

getAnother

public SequenceIterator getAnother()
Get another iterator over the same items

Returns: a new ArrayIterator

getReverseIterator

public SequenceIterator getReverseIterator()
Get an iterator that processes the same items in reverse order

Returns: a new ArrayIterator

getStringValue

public CharSequence getStringValue()
Return the string value of the current node.

Returns: the string value, as an instance of CharSequence.

Throws: NullPointerException if there is no current node

iterateAxis

public AxisIterator iterateAxis(byte axis, NodeTest test)
Return an iterator over an axis, starting at the current node.

Parameters: axis the axis to iterate over, using a constant such as CHILD test a predicate to apply to the nodes before returning them.

Throws: NullPointerException if there is no current node

moveNext

public boolean moveNext()
Move to the next node, without returning it. Returns true if there is a next node, false if the end of the sequence has been reached. After calling this method, the current node may be retrieved using the current() function.